欧拉工程第六解

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第六解:

The sum of the squares of the first ten natural numbers is, 12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is, (1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640. Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

解:

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sumSquare = 0
sum = 0
for i in range(1,101):
    sumSquare += i**2
    sum += i
print sum**2 - sumSquare